7v-2)^(1/4)+7=12

Solution for 7v-2)^(1/4)+7=12 equation:

7v-2)^(1/4)+7=12

We move all terms to the left:

7v-2)^(1/4)+7-(12)=0

We add all the numbers together, and all the variables

7v-2)^(+1/4)+7-12=0

We add all the numbers together, and all the variables

7v+1/4)+7-12=0

We multiply all the terms by the denominator


7v*4)+7-12+1=0

Wy multiply elements

28v^2=0

a = 28; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·28·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{0}{56}=0$